11003143202013 has 4 divisors (see below), whose sum is σ = 14670857602688. Its totient is φ = 7335428801340.

The previous prime is 11003143201993. The next prime is 11003143202041. The reversal of 11003143202013 is 31020234130011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11003143202013 - 2¹⁰ = 11003143200989 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11003143302013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1833857200333 + ... + 1833857200338.

It is an arithmetic number, because the mean of its divisors is an integer number (3667714400672).

Almost surely, 2^{11003143202013} is an apocalyptic number.

It is an amenable number.

11003143202013 is a deficient number, since it is larger than the sum of its proper divisors (3667714400675).

11003143202013 is an equidigital number, since it uses as much as digits as its factorization.

11003143202013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3667714400674.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11003143202013 its reverse (31020234130011), we get a palindrome (42023377332024).

The spelling of 11003143202013 in words is "eleven trillion, three billion, one hundred forty-three million, two hundred two thousand, thirteen".