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11003144344103 = 89211158565057
BaseRepresentation
bin1010000000011101111010…
…0000101001001000100111
31102221220001001021220112102
42200013132200221020213
52420233414423002403
635222435201442315
72213644113521312
oct240073640511047
942856031256472
1011003144344103
1135624531491aa
12129859694039b
1361a7909a6cb2
142a07aadd3979
1514133c761b88
hexa01de829227

11003144344103 has 8 divisors (see below), whose sum is σ = 11132046224640. Its totient is φ = 10874359598080.

The previous prime is 11003144344091. The next prime is 11003144344169. The reversal of 11003144344103 is 30144344130011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11003144344103 - 212 = 11003144340007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11003144644103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29094650 + ... + 29470407.

It is an arithmetic number, because the mean of its divisors is an integer number (1391505778080).

Almost surely, 211003144344103 is an apocalyptic number.

11003144344103 is a deficient number, since it is larger than the sum of its proper divisors (128901880537).

11003144344103 is an equidigital number, since it uses as much as digits as its factorization.

11003144344103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58567257.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 11003144344103 its reverse (30144344130011), we get a palindrome (41147488474114).

The spelling of 11003144344103 in words is "eleven trillion, three billion, one hundred forty-four million, three hundred forty-four thousand, one hundred three".

Divisors: 1 89 2111 187879 58565057 5212290073 123630835327 11003144344103