1100323101133 has 4 divisors (see below), whose sum is σ = 1118972645280. Its totient is φ = 1081673556988.

The previous prime is 1100323101131. The next prime is 1100323101167. The reversal of 1100323101133 is 3311013230011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1100323101133 - 2¹ = 1100323101131 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100323101133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100323101131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9324771985 + ... + 9324772102.

It is an arithmetic number, because the mean of its divisors is an integer number (279743161320).

Almost surely, 2^{1100323101133} is an apocalyptic number.

It is an amenable number.

1100323101133 is a deficient number, since it is larger than the sum of its proper divisors (18649544147).

1100323101133 is an equidigital number, since it uses as much as digits as its factorization.

1100323101133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18649544146.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1100323101133 its reverse (3311013230011), we get a palindrome (4411336331144).

The spelling of 1100323101133 in words is "one trillion, one hundred billion, three hundred twenty-three million, one hundred one thousand, one hundred thirty-three".