11003303130213 has 4 divisors (see below), whose sum is σ = 14671070840288. Its totient is φ = 7335535420140.

The previous prime is 11003303130203. The next prime is 11003303130223. The reversal of 11003303130213 is 31203130330011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (11003303130203) and next prime (11003303130223).

It is not a de Polignac number, because 11003303130213 - 2¹² = 11003303126117 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11003303130213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11003303130203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1833883855033 + ... + 1833883855038.

It is an arithmetic number, because the mean of its divisors is an integer number (3667767710072).

Almost surely, 2^{11003303130213} is an apocalyptic number.

It is an amenable number.

11003303130213 is a deficient number, since it is larger than the sum of its proper divisors (3667767710075).

11003303130213 is an equidigital number, since it uses as much as digits as its factorization.

11003303130213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3667767710074.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 11003303130213 its reverse (31203130330011), we get a palindrome (42206433460224).

The spelling of 11003303130213 in words is "eleven trillion, three billion, three hundred three million, one hundred thirty thousand, two hundred thirteen".