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110033214103 = 149811910577
BaseRepresentation
bin110011001111001111…
…1011001101010010111
3101112000101220102120001
41212132133121222113
53300322000322403
6122314253352131
710643503613401
oct1463637315227
9345011812501
10110033214103
114273497638a
12193a9a98647
13a4b7358b17
14547b78bb71
152cdeea8c1d
hex199e7d9a97

110033214103 has 8 divisors (see below), whose sum is σ = 110908400400. Its totient is φ = 109159850880.

The previous prime is 110033214061. The next prime is 110033214107. The reversal of 110033214103 is 301412330011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110033214103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110033214107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 334450 + ... + 576127.

It is an arithmetic number, because the mean of its divisors is an integer number (13863550050).

Almost surely, 2110033214103 is an apocalyptic number.

110033214103 is a deficient number, since it is larger than the sum of its proper divisors (875186297).

110033214103 is an equidigital number, since it uses as much as digits as its factorization.

110033214103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 911537.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 110033214103 its reverse (301412330011), we get a palindrome (411445544114).

The spelling of 110033214103 in words is "one hundred ten billion, thirty-three million, two hundred fourteen thousand, one hundred three".

Divisors: 1 149 811 120839 910577 135675973 738477947 110033214103