Base | Representation |
---|---|
bin | 10100011111101100… |
… | …10110011001111001 |
3 | 1001101211200202221110 |
4 | 22033312112121321 |
5 | 140013322332100 |
6 | 5015503230533 |
7 | 536446465611 |
oct | 121766263171 |
9 | 31354622843 |
10 | 11003324025 |
11 | 47370a9221 |
12 | 2170ba8449 |
13 | 106481c625 |
14 | 7654d7a41 |
15 | 445ee9250 |
hex | 28fd96679 |
11003324025 has 12 divisors (see below), whose sum is σ = 18192162512. Its totient is φ = 5868439440.
The previous prime is 11003324009. The next prime is 11003324041. The reversal of 11003324025 is 52042330011.
It is an interprime number because it is at equal distance from previous prime (11003324009) and next prime (11003324041).
It is not a de Polignac number, because 11003324025 - 24 = 11003324009 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11003323992 and 11003324010.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 73355419 + ... + 73355568.
Almost surely, 211003324025 is an apocalyptic number.
11003324025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11003324025 is a deficient number, since it is larger than the sum of its proper divisors (7188838487).
11003324025 is a wasteful number, since it uses less digits than its factorization.
11003324025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 146711000 (or 146710995 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 21.
Adding to 11003324025 its reverse (52042330011), we get a palindrome (63045654036).
The spelling of 11003324025 in words is "eleven billion, three million, three hundred twenty-four thousand, twenty-five".
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