Base | Representation |
---|---|
bin | 110011001111010001… |
… | …1010100111111000011 |
3 | 101112000110211201122201 |
4 | 1212132203110333003 |
5 | 3300322231243043 |
6 | 122314331414031 |
7 | 10643515431541 |
oct | 1463643247703 |
9 | 345013751581 |
10 | 110034243523 |
11 | 42735509846 |
12 | 193aa2b4317 |
13 | a4b7629549 |
14 | 547b978d91 |
15 | 2ce010dc4d |
hex | 199e8d4fc3 |
110034243523 has 4 divisors (see below), whose sum is σ = 110527670848. Its totient is φ = 109540816200.
The previous prime is 110034243497. The next prime is 110034243547. The reversal of 110034243523 is 325342430011.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110034243523 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 110034243491 and 110034243500.
It is not an unprimeable number, because it can be changed into a prime (110034247523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 246713328 + ... + 246713773.
It is an arithmetic number, because the mean of its divisors is an integer number (27631917712).
Almost surely, 2110034243523 is an apocalyptic number.
110034243523 is a deficient number, since it is larger than the sum of its proper divisors (493427325).
110034243523 is an equidigital number, since it uses as much as digits as its factorization.
110034243523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 493427324.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 110034243523 its reverse (325342430011), we get a palindrome (435376673534).
The spelling of 110034243523 in words is "one hundred ten billion, thirty-four million, two hundred forty-three thousand, five hundred twenty-three".
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