110040433214053 has 4 divisors (see below), whose sum is σ = 110086074209088. Its totient is φ = 109994792219020.

The previous prime is 110040433214029. The next prime is 110040433214057. The reversal of 110040433214053 is 350412334040011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110040433214053 - 2⁹ = 110040433213541 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110040433214057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22820493901 + ... + 22820498722.

It is an arithmetic number, because the mean of its divisors is an integer number (27521518552272).

Almost surely, 2^{110040433214053} is an apocalyptic number.

It is an amenable number.

110040433214053 is a deficient number, since it is larger than the sum of its proper divisors (45640995035).

110040433214053 is an equidigital number, since it uses as much as digits as its factorization.

110040433214053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45640995034.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 110040433214053 its reverse (350412334040011), we get a palindrome (460452767254064).

The spelling of 110040433214053 in words is "one hundred ten trillion, forty billion, four hundred thirty-three million, two hundred fourteen thousand, fifty-three".