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11004132613 = 83132579911
BaseRepresentation
bin10100011111110010…
…11011110100000101
31001101220012212010011
422033321123310011
5140014024220423
65015532430221
7536456404165
oct121771336405
931356185104
1011004132613
114737600781
122171318371
131064a43696
147656685a5
15446108b0d
hex28fe5bd05

11004132613 has 4 divisors (see below), whose sum is σ = 11136712608. Its totient is φ = 10871552620.

The previous prime is 11004132569. The next prime is 11004132641. The reversal of 11004132613 is 31623140011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11004132613 - 221 = 11002035461 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11004162613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66289873 + ... + 66290038.

It is an arithmetic number, because the mean of its divisors is an integer number (2784178152).

Almost surely, 211004132613 is an apocalyptic number.

It is an amenable number.

11004132613 is a deficient number, since it is larger than the sum of its proper divisors (132579995).

11004132613 is an equidigital number, since it uses as much as digits as its factorization.

11004132613 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 132579994.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 11004132613 its reverse (31623140011), we get a palindrome (42627272624).

The spelling of 11004132613 in words is "eleven billion, four million, one hundred thirty-two thousand, six hundred thirteen".

Divisors: 1 83 132579911 11004132613