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11004140411331 = 33668046803777
BaseRepresentation
bin1010000000100001100111…
…1000010101100111000011
31102221222121110120100220020
42200020121320111213003
52420242434421130311
635223122102544523
72214010600122354
oct240103170254703
942858543510806
1011004140411331
113562914426261
121298814438143
1361a8bc1680a2
142a08633d9d2b
15141399e17c06
hexa0219e159c3

11004140411331 has 4 divisors (see below), whose sum is σ = 14672187215112. Its totient is φ = 7336093607552.

The previous prime is 11004140411249. The next prime is 11004140411339. The reversal of 11004140411331 is 13311404140011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11004140411331 - 227 = 11004006193603 is a prime.

It is a super-2 number, since 2×110041404113312 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11004140411339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1834023401886 + ... + 1834023401891.

It is an arithmetic number, because the mean of its divisors is an integer number (3668046803778).

Almost surely, 211004140411331 is an apocalyptic number.

11004140411331 is a deficient number, since it is larger than the sum of its proper divisors (3668046803781).

11004140411331 is an equidigital number, since it uses as much as digits as its factorization.

11004140411331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3668046803780.

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 11004140411331 its reverse (13311404140011), we get a palindrome (24315544551342).

The spelling of 11004140411331 in words is "eleven trillion, four billion, one hundred forty million, four hundred eleven thousand, three hundred thirty-one".

Divisors: 1 3 3668046803777 11004140411331