Base | Representation |
---|---|
bin | 10100011111110011… |
… | …10000000000011011 |
3 | 1001101220101001120111 |
4 | 22033321300000123 |
5 | 140014034342243 |
6 | 5015534305151 |
7 | 536460200263 |
oct | 121771600033 |
9 | 31356331514 |
10 | 11004215323 |
11 | 4737657932 |
12 | 21713581b7 |
13 | 1064a7221a |
14 | 76568a7a3 |
15 | 44612339d |
hex | 28fe7001b |
11004215323 has 4 divisors (see below), whose sum is σ = 11012026680. Its totient is φ = 10996403968.
The previous prime is 11004215279. The next prime is 11004215393. The reversal of 11004215323 is 32351240011.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32351240011 = 5503 ⋅5878837.
It is a cyclic number.
It is not a de Polignac number, because 11004215323 - 213 = 11004207131 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11004215294 and 11004215303.
It is not an unprimeable number, because it can be changed into a prime (11004215393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3903565 + ... + 3906382.
It is an arithmetic number, because the mean of its divisors is an integer number (2753006670).
Almost surely, 211004215323 is an apocalyptic number.
11004215323 is a deficient number, since it is larger than the sum of its proper divisors (7811357).
11004215323 is an equidigital number, since it uses as much as digits as its factorization.
11004215323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7811356.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 11004215323 its reverse (32351240011), we get a palindrome (43355455334).
The spelling of 11004215323 in words is "eleven billion, four million, two hundred fifteen thousand, three hundred twenty-three".
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