1100430314 has 4 divisors (see below), whose sum is σ = 1650645474. Its totient is φ = 550215156.

The previous prime is 1100430257. The next prime is 1100430323. The reversal of 1100430314 is 4130340011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4130340011 = 7 ⋅590048573.

It can be written as a sum of positive squares in only one way, i.e., 799928089 + 300502225 = 28283^2 + 17335^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1100430292 and 1100430301.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275107577 + ... + 275107580.

Almost surely, 2^1100430314 is an apocalyptic number.

1100430314 is a deficient number, since it is larger than the sum of its proper divisors (550215160).

1100430314 is an equidigital number, since it uses as much as digits as its factorization.

1100430314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 550215159.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1100430314 is about 33172.7344968726. The cubic root of 1100430314 is about 1032.4147053578.

Adding to 1100430314 its reverse (4130340011), we get a palindrome (5230770325).

The spelling of 1100430314 in words is "one billion, one hundred million, four hundred thirty thousand, three hundred fourteen".