11004424124031 has 80 divisors (see below), whose sum is σ = 18162004032480. Its totient is φ = 6596949381120.

The previous prime is 11004424124027. The next prime is 11004424124069. The reversal of 11004424124031 is 13042142440011.

11004424124031 is a `hidden beast` number, since 1 + 10 + 0 + 4 + 4 + 241 + 2 + 403 + 1 = 666.

11004424124031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11004424124031 - 2² = 11004424124027 is a prime.

It is a super-2 number, since 2×11004424124031² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 11004424123986 and 11004424124004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11004424124011) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 28866060 + ... + 29244798.

It is an arithmetic number, because the mean of its divisors is an integer number (227025050406).

Almost surely, 2^{11004424124031} is an apocalyptic number.

11004424124031 is a deficient number, since it is larger than the sum of its proper divisors (7157579908449).

11004424124031 is a wasteful number, since it uses less digits than its factorization.

11004424124031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 379478 (or 379469 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 27.

Adding to 11004424124031 its reverse (13042142440011), we get a palindrome (24046566564042).

The spelling of 11004424124031 in words is "eleven trillion, four billion, four hundred twenty-four million, one hundred twenty-four thousand, thirty-one".