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110045312353 = 151728776903
BaseRepresentation
bin110011001111100110…
…1100011010101100001
3101112001020200002020101
41212133031203111201
53300333044443403
6122315404542401
710644011502304
oct1463715432541
9345036602211
10110045312353
1142740789a39
12193b1b51a01
13a4b9a03752
14547d21ab3b
152ce109871d
hex199f363561

110045312353 has 4 divisors (see below), whose sum is σ = 110774089408. Its totient is φ = 109316535300.

The previous prime is 110045312329. The next prime is 110045312357. The reversal of 110045312353 is 353213540011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110045312353 - 29 = 110045311841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110045312357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 364388301 + ... + 364388602.

It is an arithmetic number, because the mean of its divisors is an integer number (27693522352).

Almost surely, 2110045312353 is an apocalyptic number.

It is an amenable number.

110045312353 is a deficient number, since it is larger than the sum of its proper divisors (728777055).

110045312353 is an equidigital number, since it uses as much as digits as its factorization.

110045312353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 728777054.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 110045312353 its reverse (353213540011), we get a palindrome (463258852364).

The spelling of 110045312353 in words is "one hundred ten billion, forty-five million, three hundred twelve thousand, three hundred fifty-three".

Divisors: 1 151 728776903 110045312353