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11005000555 = 523211345289
BaseRepresentation
bin10100011111111001…
…01111101101101011
31001101221211221201011
422033330233231223
5140014240004210
65020003204351
7536466650503
oct121774575553
931357757634
1011005000555
11473804388a
1221716766b7
131064c88763
14765812a03
1544622ad8a
hex28ff2fb6b

11005000555 has 16 divisors (see below), whose sum is σ = 13787000640. Its totient is φ = 8417046528.

The previous prime is 11005000493. The next prime is 11005000607. The reversal of 11005000555 is 55500050011.

It is a cyclic number.

It is not a de Polignac number, because 11005000555 - 211 = 11004998507 is a prime.

It is a super-3 number, since 3×110050005553 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 220351 + ... + 265639.

It is an arithmetic number, because the mean of its divisors is an integer number (861687540).

Almost surely, 211005000555 is an apocalyptic number.

11005000555 is a deficient number, since it is larger than the sum of its proper divisors (2782000085).

11005000555 is a wasteful number, since it uses less digits than its factorization.

11005000555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47430.

The product of its (nonzero) digits is 625, while the sum is 22.

Adding to 11005000555 its reverse (55500050011), we get a palindrome (66505050566).

The spelling of 11005000555 in words is "eleven billion, five million, five hundred fifty-five", and thus it is an aban number.

Divisors: 1 5 23 115 2113 10565 45289 48599 226445 242995 1041647 5208235 95695657 478478285 2201000111 11005000555