Base | Representation |
---|---|
bin | 10100011111111001… |
… | …01111101101101011 |
3 | 1001101221211221201011 |
4 | 22033330233231223 |
5 | 140014240004210 |
6 | 5020003204351 |
7 | 536466650503 |
oct | 121774575553 |
9 | 31357757634 |
10 | 11005000555 |
11 | 473804388a |
12 | 21716766b7 |
13 | 1064c88763 |
14 | 765812a03 |
15 | 44622ad8a |
hex | 28ff2fb6b |
11005000555 has 16 divisors (see below), whose sum is σ = 13787000640. Its totient is φ = 8417046528.
The previous prime is 11005000493. The next prime is 11005000607. The reversal of 11005000555 is 55500050011.
It is a cyclic number.
It is not a de Polignac number, because 11005000555 - 211 = 11004998507 is a prime.
It is a super-3 number, since 3×110050005553 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 220351 + ... + 265639.
It is an arithmetic number, because the mean of its divisors is an integer number (861687540).
Almost surely, 211005000555 is an apocalyptic number.
11005000555 is a deficient number, since it is larger than the sum of its proper divisors (2782000085).
11005000555 is a wasteful number, since it uses less digits than its factorization.
11005000555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47430.
The product of its (nonzero) digits is 625, while the sum is 22.
Adding to 11005000555 its reverse (55500050011), we get a palindrome (66505050566).
The spelling of 11005000555 in words is "eleven billion, five million, five hundred fifty-five", and thus it is an aban number.
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