Base | Representation |
---|---|
bin | 10100011111111011… |
… | …00001101000001011 |
3 | 1001101222020100011022 |
4 | 22033331201220023 |
5 | 140014313030003 |
6 | 5020011423055 |
7 | 536501461532 |
oct | 121775415013 |
9 | 31358210138 |
10 | 11005205003 |
11 | 4738173451 |
12 | 2171754a8b |
13 | 106502a830 |
14 | 765867319 |
15 | 44626b738 |
hex | 28ff61a0b |
11005205003 has 8 divisors (see below), whose sum is σ = 12234074496. Its totient is φ = 9830952000.
The previous prime is 11005204993. The next prime is 11005205039. The reversal of 11005205003 is 30050250011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11005205003 - 28 = 11005204747 is a prime.
It is a super-4 number, since 4×110052050034 (a number of 41 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11005205063) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13653698 + ... + 13654503.
It is an arithmetic number, because the mean of its divisors is an integer number (1529259312).
Almost surely, 211005205003 is an apocalyptic number.
11005205003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11005205003 is a deficient number, since it is larger than the sum of its proper divisors (1228869493).
11005205003 is a wasteful number, since it uses less digits than its factorization.
11005205003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27308245.
The product of its (nonzero) digits is 150, while the sum is 17.
Adding to 11005205003 its reverse (30050250011), we get a palindrome (41055455014).
The spelling of 11005205003 in words is "eleven billion, five million, two hundred five thousand, three".
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