Base | Representation |
---|---|
bin | 10100011111111011… |
… | …00001101000000001 |
3 | 1001101222020100010221 |
4 | 22033331201220001 |
5 | 140014313024433 |
6 | 5020011423041 |
7 | 536501461516 |
oct | 121775415001 |
9 | 31358210127 |
10 | 11005204993 |
11 | 4738173442 |
12 | 2171754a81 |
13 | 106502a823 |
14 | 76586730d |
15 | 44626b72d |
hex | 28ff61a01 |
11005204993 has 2 divisors, whose sum is σ = 11005204994. Its totient is φ = 11005204992.
The previous prime is 11005204967. The next prime is 11005205039. The reversal of 11005204993 is 39940250011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5980238224 + 5024966769 = 77332^2 + 70887^2 .
It is a cyclic number.
It is not a de Polignac number, because 11005204993 - 29 = 11005204481 is a prime.
It is a super-2 number, since 2×110052049932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11005204943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502602496 + 5502602497.
It is an arithmetic number, because the mean of its divisors is an integer number (5502602497).
Almost surely, 211005204993 is an apocalyptic number.
It is an amenable number.
11005204993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11005204993 is an equidigital number, since it uses as much as digits as its factorization.
11005204993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 34.
The spelling of 11005204993 in words is "eleven billion, five million, two hundred four thousand, nine hundred ninety-three".
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