Base | Representation |
---|---|
bin | 10100011111111100… |
… | …00001011110010010 |
3 | 1001101222110222002101 |
4 | 22033332001132102 |
5 | 140014331213232 |
6 | 5020014311014 |
7 | 536502544033 |
oct | 121776013622 |
9 | 31358428071 |
10 | 11005335442 |
11 | 4738252452 |
12 | 21717b846a |
13 | 106507500a |
14 | 76589ca8a |
15 | 4462951e7 |
hex | 28ff81792 |
11005335442 has 4 divisors (see below), whose sum is σ = 16508003166. Its totient is φ = 5502667720.
The previous prime is 11005335427. The next prime is 11005335443. The reversal of 11005335442 is 24453350011.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24453350011 = 41 ⋅596423171.
It can be written as a sum of positive squares in only one way, i.e., 7279331761 + 3726003681 = 85319^2 + 61041^2 .
It is a super-2 number, since 2×110053354422 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11005335442.
It is not an unprimeable number, because it can be changed into a prime (11005335443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2751333859 + ... + 2751333862.
Almost surely, 211005335442 is an apocalyptic number.
11005335442 is a deficient number, since it is larger than the sum of its proper divisors (5502667724).
11005335442 is an equidigital number, since it uses as much as digits as its factorization.
11005335442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5502667723.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 11005335442 its reverse (24453350011), we get a palindrome (35458685453).
The spelling of 11005335442 in words is "eleven billion, five million, three hundred thirty-five thousand, four hundred forty-two".
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