11006110053 has 6 divisors (see below), whose sum is σ = 15897714534. Its totient is φ = 7337406696.

The previous prime is 11006110051. The next prime is 11006110057. The reversal of 11006110053 is 35001160011.

11006110053 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 611 + 0 + 0 + 53 = 666.

It can be written as a sum of positive squares in only one way, i.e., 7662726369 + 3343383684 = 87537^2 + 57822^2 .

It is not a de Polignac number, because 11006110053 - 2¹ = 11006110051 is a prime.

It is a super-3 number, since 3×11006110053³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11006110051) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 611450550 + ... + 611450567.

It is an arithmetic number, because the mean of its divisors is an integer number (2649619089).

Almost surely, 2^11006110053 is an apocalyptic number.

It is an amenable number.

11006110053 is a deficient number, since it is larger than the sum of its proper divisors (4891604481).

11006110053 is a wasteful number, since it uses less digits than its factorization.

11006110053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1222901123 (or 1222901120 counting only the distinct ones).

The product of its (nonzero) digits is 90, while the sum is 18.

Adding to 11006110053 its reverse (35001160011), we get a palindrome (46007270064).

The spelling of 11006110053 in words is "eleven billion, six million, one hundred ten thousand, fifty-three".