1100612049807 has 4 divisors (see below), whose sum is σ = 1467482733080. Its totient is φ = 733741366536.

The previous prime is 1100612049793. The next prime is 1100612049827. The reversal of 1100612049807 is 7089402160011.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1100612049807 - 2⁷ = 1100612049679 is a prime.

It is a super-2 number, since 2×1100612049807² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100612049827) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183435341632 + ... + 183435341637.

It is an arithmetic number, because the mean of its divisors is an integer number (366870683270).

Almost surely, 2^{1100612049807} is an apocalyptic number.

1100612049807 is a deficient number, since it is larger than the sum of its proper divisors (366870683273).

1100612049807 is an equidigital number, since it uses as much as digits as its factorization.

1100612049807 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 366870683272.

The product of its (nonzero) digits is 24192, while the sum is 39.

The spelling of 1100612049807 in words is "one trillion, one hundred billion, six hundred twelve million, forty-nine thousand, eight hundred seven".