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11006230502151 = 3210311872956313
BaseRepresentation
bin1010000000101001011001…
…1101011001101100000111
31102222012000010102222111100
42200022112131121230013
52420311230002032101
635224105324511143
72214113436445533
oct240122635315407
942865003388440
1011006230502151
113563797206445
1212990b83ab4b3
1361ab63196811
142a09c0c26bc3
1514146d673e86
hexa0296759b07

11006230502151 has 12 divisors (see below), whose sum is σ = 16052236936528. Its totient is φ = 7266249262944.

The previous prime is 11006230502143. The next prime is 11006230502161. The reversal of 11006230502151 is 15120503260011.

11006230502151 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 6 + 2 + 3 + 0 + 502 + 151 = 666.

It is not a de Polignac number, because 11006230502151 - 23 = 11006230502143 is a prime.

It is a super-2 number, since 2×110062305021512 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11006230502161) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5936477230 + ... + 5936479083.

Almost surely, 211006230502151 is an apocalyptic number.

11006230502151 is a deficient number, since it is larger than the sum of its proper divisors (5046006434377).

11006230502151 is a wasteful number, since it uses less digits than its factorization.

11006230502151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11872956422 (or 11872956419 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 27.

Adding to 11006230502151 its reverse (15120503260011), we get a palindrome (26126733762162).

The spelling of 11006230502151 in words is "eleven trillion, six billion, two hundred thirty million, five hundred two thousand, one hundred fifty-one".

Divisors: 1 3 9 103 309 927 11872956313 35618868939 106856606817 1222914500239 3668743500717 11006230502151