11006453413661 has 4 divisors (see below), whose sum is σ = 11006964816192. Its totient is φ = 11005942011132.

The previous prime is 11006453413651. The next prime is 11006453413679. The reversal of 11006453413661 is 16631435460011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11006453413661 is a prime.

It is a super-2 number, since 2×11006453413661² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11006453413601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255668981 + ... + 255712026.

It is an arithmetic number, because the mean of its divisors is an integer number (2751741204048).

Almost surely, 2^{11006453413661} is an apocalyptic number.

It is an amenable number.

11006453413661 is a deficient number, since it is larger than the sum of its proper divisors (511402531).

11006453413661 is an equidigital number, since it uses as much as digits as its factorization.

11006453413661 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 511402530.

The product of its (nonzero) digits is 155520, while the sum is 41.

Adding to 11006453413661 its reverse (16631435460011), we get a palindrome (27637888873672).

The spelling of 11006453413661 in words is "eleven trillion, six billion, four hundred fifty-three million, four hundred thirteen thousand, six hundred sixty-one".