Base | Representation |
---|---|
bin | 1010000000110100101100… |
… | …1000110000111011010011 |
3 | 1102222110211101022021001210 |
4 | 2200031023020300323103 |
5 | 2420333432003042103 |
6 | 35225330211231203 |
7 | 2214251525002503 |
oct | 240151310607323 |
9 | 42873741267053 |
10 | 11009261768403 |
11 | 3565002291668 |
12 | 12998035a8503 |
13 | 61b2271a74a2 |
14 | 2a0bcb64ba03 |
15 | 141599841e03 |
hex | a034b230ed3 |
11009261768403 has 8 divisors (see below), whose sum is σ = 14681967453648. Its totient is φ = 7338031964384.
The previous prime is 11009261768387. The next prime is 11009261768413. The reversal of 11009261768403 is 30486716290011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11009261768403 - 24 = 11009261768387 is a prime.
It is a super-3 number, since 3×110092617684033 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11009261768413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 368952900 + ... + 368982737.
It is an arithmetic number, because the mean of its divisors is an integer number (1835245931706).
Almost surely, 211009261768403 is an apocalyptic number.
11009261768403 is a deficient number, since it is larger than the sum of its proper divisors (3672705685245).
11009261768403 is an equidigital number, since it uses as much as digits as its factorization.
11009261768403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 737940613.
The product of its (nonzero) digits is 435456, while the sum is 48.
The spelling of 11009261768403 in words is "eleven trillion, nine billion, two hundred sixty-one million, seven hundred sixty-eight thousand, four hundred three".
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