11009445529645 has 4 divisors (see below), whose sum is σ = 13211334635580. Its totient is φ = 8807556423712.

The previous prime is 11009445529637. The next prime is 11009445529681. The reversal of 11009445529645 is 54692554490011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6416387897481 + 4593057632164 = 2533059^2 + 2143142^2 .

It is a cyclic number.

It is not a de Polignac number, because 11009445529645 - 2³ = 11009445529637 is a prime.

It is a super-3 number, since 3×11009445529645³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1100944552960 + ... + 1100944552969.

It is an arithmetic number, because the mean of its divisors is an integer number (3302833658895).

Almost surely, 2^{11009445529645} is an apocalyptic number.

It is an amenable number.

11009445529645 is a deficient number, since it is larger than the sum of its proper divisors (2201889105935).

11009445529645 is an equidigital number, since it uses as much as digits as its factorization.

11009445529645 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2201889105934.

The product of its (nonzero) digits is 7776000, while the sum is 55.

The spelling of 11009445529645 in words is "eleven trillion, nine billion, four hundred forty-five million, five hundred twenty-nine thousand, six hundred forty-five".