11009993 has 4 divisors (see below), whose sum is σ = 11149440. Its totient is φ = 10870548.

The previous prime is 11009989. The next prime is 11010007. The reversal of 11009993 is 39990011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11009993 - 2² = 11009989 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11009953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69605 + ... + 69762.

It is an arithmetic number, because the mean of its divisors is an integer number (2787360).

Almost surely, 2^11009993 is an apocalyptic number.

It is an amenable number.

11009993 is a deficient number, since it is larger than the sum of its proper divisors (139447).

11009993 is an equidigital number, since it uses as much as digits as its factorization.

11009993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139446.

The product of its (nonzero) digits is 2187, while the sum is 32.

The square root of 11009993 is about 3318.1309497969. The cubic root of 11009993 is about 222.4653348343.

The spelling of 11009993 in words is "eleven million, nine thousand, nine hundred ninety-three".