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110100431314 = 255050215657
BaseRepresentation
bin110011010001001111…
…1110100000111010010
3101112012002101102020101
41212202133310013102
53300441202300224
6122325054203014
710645251140056
oct1464237640722
9345162342211
10110100431314
11427699066a5
12194084b346a
13a4c8261b13
145486687c66
152ce5d35044
hex19a27f41d2

110100431314 has 4 divisors (see below), whose sum is σ = 165150646974. Its totient is φ = 55050215656.

The previous prime is 110100431297. The next prime is 110100431323. The reversal of 110100431314 is 413134001011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 109417393089 + 683038225 = 330783^2 + 26135^2 .

It is a junction number, because it is equal to n+sod(n) for n = 110100431291 and 110100431300.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27525107827 + ... + 27525107830.

Almost surely, 2110100431314 is an apocalyptic number.

110100431314 is a deficient number, since it is larger than the sum of its proper divisors (55050215660).

110100431314 is an equidigital number, since it uses as much as digits as its factorization.

110100431314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55050215659.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 110100431314 its reverse (413134001011), we get a palindrome (523234432325).

The spelling of 110100431314 in words is "one hundred ten billion, one hundred million, four hundred thirty-one thousand, three hundred fourteen".

Divisors: 1 2 55050215657 110100431314