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11010110057 = 79071392451
BaseRepresentation
bin10100100000100000…
…01111001001101001
31001102022110112121222
422100100033021221
5140022042010212
65020304511425
7536561251142
oct122020171151
931368415558
1011010110057
11473aa13711
12217331b575
13106605732b
14766382ac9
154468d9c72
hex29040f269

11010110057 has 4 divisors (see below), whose sum is σ = 11011510416. Its totient is φ = 11008709700.

The previous prime is 11010110047. The next prime is 11010110099. The reversal of 11010110057 is 75001101011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11010110057 - 28 = 11010109801 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11010110047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 688319 + ... + 704132.

It is an arithmetic number, because the mean of its divisors is an integer number (2752877604).

Almost surely, 211010110057 is an apocalyptic number.

It is an amenable number.

11010110057 is a deficient number, since it is larger than the sum of its proper divisors (1400359).

11010110057 is an equidigital number, since it uses as much as digits as its factorization.

11010110057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1400358.

The product of its (nonzero) digits is 35, while the sum is 17.

Adding to 11010110057 its reverse (75001101011), we get a palindrome (86011211068).

The spelling of 11010110057 in words is "eleven billion, ten million, one hundred ten thousand, fifty-seven".

Divisors: 1 7907 1392451 11010110057