Base | Representation |
---|---|
bin | 11001000010001011101010… |
… | …110111010000100111111111 |
3 | 112102211120021012021201011201 |
4 | 121002023222313100213333 |
5 | 103412344104244121343 |
6 | 1030055432314000331 |
7 | 32122354455512551 |
oct | 3102135267204777 |
9 | 472746235251151 |
10 | 110101132020223 |
11 | 3209969a7708a3 |
12 | 104224064160a7 |
13 | 4958652493246 |
14 | 1d28ccd4774d1 |
15 | cadeb300a94d |
hex | 6422eadd09ff |
110101132020223 has 4 divisors (see below), whose sum is σ = 115895928442360. Its totient is φ = 104306335598088.
The previous prime is 110101132020221. The next prime is 110101132020239. The reversal of 110101132020223 is 322020231101011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 110101132020223 - 21 = 110101132020221 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 5794796422117 = 110101132020223 / (1 + 1 + 0 + 1 + 0 + 1 + 1 + 3 + 2 + 0 + 2 + 0 + 2 + 2 + 3).
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 110101132020223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110101132020221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2897398211040 + ... + 2897398211077.
It is an arithmetic number, because the mean of its divisors is an integer number (28973982110590).
Almost surely, 2110101132020223 is an apocalyptic number.
110101132020223 is a deficient number, since it is larger than the sum of its proper divisors (5794796422137).
110101132020223 is an equidigital number, since it uses as much as digits as its factorization.
110101132020223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5794796422136.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 110101132020223 its reverse (322020231101011), we get a palindrome (432121363121234).
The spelling of 110101132020223 in words is "one hundred ten trillion, one hundred one billion, one hundred thirty-two million, twenty thousand, two hundred twenty-three".
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