11010150053 has 4 divisors (see below), whose sum is σ = 12583028640. Its totient is φ = 9437271468.

The previous prime is 11010150049. The next prime is 11010150089. The reversal of 11010150053 is 35005101011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35005101011 = 151 ⋅231821861.

It is a cyclic number.

It is not a de Polignac number, because 11010150053 - 2² = 11010150049 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11010150953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786439283 + ... + 786439296.

It is an arithmetic number, because the mean of its divisors is an integer number (3145757160).

Almost surely, 2^11010150053 is an apocalyptic number.

It is an amenable number.

11010150053 is a deficient number, since it is larger than the sum of its proper divisors (1572878587).

11010150053 is an equidigital number, since it uses as much as digits as its factorization.

11010150053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1572878586.

The product of its (nonzero) digits is 75, while the sum is 17.

Adding to 11010150053 its reverse (35005101011), we get a palindrome (46015251064).

The spelling of 11010150053 in words is "eleven billion, ten million, one hundred fifty thousand, fifty-three".