Base | Representation |
---|---|
bin | 1010000000111000100101… |
… | …0001001001111100101001 |
3 | 1102222120112000202000020211 |
4 | 2200032021101021330221 |
5 | 2420343100330433213 |
6 | 35230021445221121 |
7 | 2214316413102652 |
oct | 240161121117451 |
9 | 42876460660224 |
10 | 11010304155433 |
11 | 3565497726450 |
12 | 1299a547017a1 |
13 | 61b36213584b |
14 | 2a0c89c70529 |
15 | 14160b0e753d |
hex | a0389449f29 |
11010304155433 has 32 divisors (see below), whose sum is σ = 12254961059712. Its totient is φ = 9808132953600.
The previous prime is 11010304155379. The next prime is 11010304155443. The reversal of 11010304155433 is 33455140301011.
It is a cyclic number.
It is not a de Polignac number, because 11010304155433 - 29 = 11010304154921 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11010304155395 and 11010304155404.
It is not an unprimeable number, because it can be changed into a prime (11010304155443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 198209643 + ... + 198265183.
It is an arithmetic number, because the mean of its divisors is an integer number (382967533116).
Almost surely, 211010304155433 is an apocalyptic number.
It is an amenable number.
11010304155433 is a deficient number, since it is larger than the sum of its proper divisors (1244656904279).
11010304155433 is a wasteful number, since it uses less digits than its factorization.
11010304155433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57225.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 11010304155433 its reverse (33455140301011), we get a palindrome (44465444456444).
The spelling of 11010304155433 in words is "eleven trillion, ten billion, three hundred four million, one hundred fifty-five thousand, four hundred thirty-three".
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