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1101032013131 = 5320774188927
BaseRepresentation
bin10000000001011010100…
…111110011110101001011
310220020221210222110121022
4100001122213303311023
5121014403143410011
62201450201103055
7142355412460121
oct20013247636513
93806853873538
101101032013131
11394a4395a806
12159479487a8b
137ca9984382b
143b40c589911
151d9913a78db
hex1005a9f3d4b

1101032013131 has 4 divisors (see below), whose sum is σ = 1121806202112. Its totient is φ = 1080257824152.

The previous prime is 1101032013121. The next prime is 1101032013203. The reversal of 1101032013131 is 1313102301011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1101032013131 - 214 = 1101031996747 is a prime.

It is a super-2 number, since 2×11010320131312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1101032013121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10387094411 + ... + 10387094516.

It is an arithmetic number, because the mean of its divisors is an integer number (280451550528).

Almost surely, 21101032013131 is an apocalyptic number.

1101032013131 is a deficient number, since it is larger than the sum of its proper divisors (20774188981).

1101032013131 is an equidigital number, since it uses as much as digits as its factorization.

1101032013131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20774188980.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1101032013131 its reverse (1313102301011), we get a palindrome (2414134314142).

The spelling of 1101032013131 in words is "one trillion, one hundred one billion, thirty-two million, thirteen thousand, one hundred thirty-one".

Divisors: 1 53 20774188927 1101032013131