Base | Representation |
---|---|
bin | 1010000000111000101011… |
… | …0011111111100010100001 |
3 | 1102222120120211111100120112 |
4 | 2200032022303333202201 |
5 | 2420343123444040212 |
6 | 35230024212421105 |
7 | 2214320146244141 |
oct | 240161263774241 |
9 | 42876524440515 |
10 | 11010330065057 |
11 | 3565500312764 |
12 | 1299a61317795 |
13 | 61b367607a9b |
14 | 2a0c8d496921 |
15 | 14160d514422 |
hex | a038acff8a1 |
11010330065057 has 4 divisors (see below), whose sum is σ = 11010650474496. Its totient is φ = 11010009655620.
The previous prime is 11010330065039. The next prime is 11010330065071. The reversal of 11010330065057 is 75056003301011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11010330065057 - 220 = 11010329016481 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11010330062057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160153169 + ... + 160221902.
It is an arithmetic number, because the mean of its divisors is an integer number (2752662618624).
Almost surely, 211010330065057 is an apocalyptic number.
It is an amenable number.
11010330065057 is a deficient number, since it is larger than the sum of its proper divisors (320409439).
11010330065057 is an equidigital number, since it uses as much as digits as its factorization.
11010330065057 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 320409438.
The product of its (nonzero) digits is 9450, while the sum is 32.
Adding to 11010330065057 its reverse (75056003301011), we get a palindrome (86066333366068).
The spelling of 11010330065057 in words is "eleven trillion, ten billion, three hundred thirty million, sixty-five thousand, fifty-seven".
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