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1101100101133 = 10511047668983
BaseRepresentation
bin10000000001011110101…
…011100010111000001101
310220021010120002200210011
4100001132223202320031
5121020023111214013
62201501032313221
7142360200301324
oct20013653427015
93807116080704
101101100101133
11394a7933528a
12159498242811
137caaa992ca6
143b4176310bb
151d997356c3d
hex1005eae2e0d

1101100101133 has 4 divisors (see below), whose sum is σ = 1102147771168. Its totient is φ = 1100052431100.

The previous prime is 1101100101121. The next prime is 1101100101149. The reversal of 1101100101133 is 3311010011011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1101100101133 - 29 = 1101100100621 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101100101533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 523833441 + ... + 523835542.

It is an arithmetic number, because the mean of its divisors is an integer number (275536942792).

Almost surely, 21101100101133 is an apocalyptic number.

It is an amenable number.

1101100101133 is a deficient number, since it is larger than the sum of its proper divisors (1047670035).

1101100101133 is a wasteful number, since it uses less digits than its factorization.

1101100101133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1047670034.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 1101100101133 its reverse (3311010011011), we get a palindrome (4412110112144).

The spelling of 1101100101133 in words is "one trillion, one hundred one billion, one hundred million, one hundred one thousand, one hundred thirty-three".

Divisors: 1 1051 1047668983 1101100101133