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11011101110983 = 49651122176953
BaseRepresentation
bin1010000000111011100011…
…0001010011001011000111
31102222122120120100112202001
42200032320301103023013
52420401213341022413
635230232514530131
72214345231106351
oct240167061231307
942878516315661
1011011101110983
1135658665779a6
12129a037596947
1361b45b290a8c
142a0d23a460d1
1514165606c4dd
hexa03b8c532c7

11011101110983 has 4 divisors (see below), whose sum is σ = 11011123784448. Its totient is φ = 11011078437520.

The previous prime is 11011101110963. The next prime is 11011101111001. The reversal of 11011101110983 is 38901110111011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11011101110983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11011101110963) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10591966 + ... + 11584987.

It is an arithmetic number, because the mean of its divisors is an integer number (2752780946112).

Almost surely, 211011101110983 is an apocalyptic number.

11011101110983 is a deficient number, since it is larger than the sum of its proper divisors (22673465).

11011101110983 is an equidigital number, since it uses as much as digits as its factorization.

11011101110983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22673464.

The product of its (nonzero) digits is 216, while the sum is 28.

Adding to 11011101110983 its reverse (38901110111011), we get a palindrome (49912211221994).

The spelling of 11011101110983 in words is "eleven trillion, eleven billion, one hundred one million, one hundred ten thousand, nine hundred eighty-three".

Divisors: 1 496511 22176953 11011101110983