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1101113113320 = 23335111073312617
BaseRepresentation
bin10000000001011111011…
…101001011101011101000
310220021011110120210011000
4100001133131023223220
5121020034424111240
62201502215235000
7142360416014613
oct20013735135350
93807143523130
101101113113320
11394a85712560
121594a0678a60
137cab059a8cc
143b41925b17a
151d998577430
hex1005f74bae8

1101113113320 has 512 divisors, whose sum is σ = 4055227545600. Its totient is φ = 263542118400.

The previous prime is 1101113113313. The next prime is 1101113113337. The reversal of 1101113113320 is 233113111011.

1101113113320 is a `hidden beast` number, since 1 + 10 + 1 + 11 + 311 + 332 + 0 = 666.

It is a super-2 number, since 2×11011131133202 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1101113113293 and 1101113113302.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 420752652 + ... + 420755268.

It is an arithmetic number, because the mean of its divisors is an integer number (7920366300).

Almost surely, 21101113113320 is an apocalyptic number.

1101113113320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1101113113320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2027613772800).

1101113113320 is an abundant number, since it is smaller than the sum of its proper divisors (2954114432280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1101113113320 is a wasteful number, since it uses less digits than its factorization.

1101113113320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3086 (or 3076 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 1101113113320 its reverse (233113111011), we get a palindrome (1334226224331).

The spelling of 1101113113320 in words is "one trillion, one hundred one billion, one hundred thirteen million, one hundred thirteen thousand, three hundred twenty".