1101121332019 has 4 divisors (see below), whose sum is σ = 1101128068296. Its totient is φ = 1101114595744.

The previous prime is 1101121331953. The next prime is 1101121332079. The reversal of 1101121332019 is 9102331211011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1101121332019 - 2⁹ = 1101121331507 is a prime.

It is a super-2 number, since 2×1101121332019² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1101121331984 and 1101121332002.

It is not an unprimeable number, because it can be changed into a prime (1101121332079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3116689 + ... + 3451954.

It is an arithmetic number, because the mean of its divisors is an integer number (275282017074).

Almost surely, 2^{1101121332019} is an apocalyptic number.

1101121332019 is a deficient number, since it is larger than the sum of its proper divisors (6736277).

1101121332019 is an equidigital number, since it uses as much as digits as its factorization.

1101121332019 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6736276.

The product of its (nonzero) digits is 324, while the sum is 25.

The spelling of 1101121332019 in words is "one trillion, one hundred one billion, one hundred twenty-one million, three hundred thirty-two thousand, nineteen".