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1101130201303 = 11100102745573
BaseRepresentation
bin10000000001100000011…
…110010111100011010111
310220021012122201221110021
4100001200132113203113
5121020103312420203
62201504025410011
7142361014165036
oct20014036274327
93807178657407
101101130201303
11394a94323a60
121594a6339907
137cab3ca1742
143b41b62871d
151d999d005bd
hex100607978d7

1101130201303 has 4 divisors (see below), whose sum is σ = 1201232946888. Its totient is φ = 1001027455720.

The previous prime is 1101130201291. The next prime is 1101130201333. The reversal of 1101130201303 is 3031020311011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1101130201303 - 221 = 1101128104151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101130201333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50051372776 + ... + 50051372797.

It is an arithmetic number, because the mean of its divisors is an integer number (300308236722).

Almost surely, 21101130201303 is an apocalyptic number.

1101130201303 is a deficient number, since it is larger than the sum of its proper divisors (100102745585).

1101130201303 is a wasteful number, since it uses less digits than its factorization.

1101130201303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100102745584.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1101130201303 its reverse (3031020311011), we get a palindrome (4132150512314).

The spelling of 1101130201303 in words is "one trillion, one hundred one billion, one hundred thirty million, two hundred one thousand, three hundred three".

Divisors: 1 11 100102745573 1101130201303