Base | Representation |
---|---|
bin | 10000000001100000100… |
… | …010100110111111001111 |
3 | 10220021012201211102120001 |
4 | 100001200202212333033 |
5 | 121020104104004403 |
6 | 2201504105305131 |
7 | 142361026505323 |
oct | 20014042467717 |
9 | 3807181742501 |
10 | 1101131313103 |
11 | 394a94a132a8 |
12 | 1594a67951a7 |
13 | 7cab42a0803 |
14 | 3b41b837983 |
15 | 1d999e6ec1d |
hex | 100608a6fcf |
1101131313103 has 8 divisors (see below), whose sum is σ = 1159098361200. Its totient is φ = 1043165541888.
The previous prime is 1101131313097. The next prime is 1101131313131. The reversal of 1101131313103 is 3013131311011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1101131313103 - 25 = 1101131313071 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1101131313703) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1817775 + ... + 2346607.
It is an arithmetic number, because the mean of its divisors is an integer number (144887295150).
Almost surely, 21101131313103 is an apocalyptic number.
1101131313103 is a deficient number, since it is larger than the sum of its proper divisors (57967048097).
1101131313103 is a wasteful number, since it uses less digits than its factorization.
1101131313103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 638441.
The product of its (nonzero) digits is 81, while the sum is 19.
Adding to 1101131313103 its reverse (3013131311011), we get a palindrome (4114262624114).
The spelling of 1101131313103 in words is "one trillion, one hundred one billion, one hundred thirty-one million, three hundred thirteen thousand, one hundred three".
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