110120100113 has 4 divisors (see below), whose sum is σ = 110249198388. Its totient is φ = 109991001840.

The previous prime is 110120100047. The next prime is 110120100119. The reversal of 110120100113 is 311001021011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311001021011 = 157 ⋅1980898223.

It can be written as a sum of positive squares in 2 ways, for example, as 2517731329 + 107602368784 = 50177^2 + 328028^2 .

It is a cyclic number.

It is not a de Polignac number, because 110120100113 - 2⁸ = 110120099857 is a prime.

It is a super-2 number, since 2×110120100113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110120100094 and 110120100103.

It is not an unprimeable number, because it can be changed into a prime (110120100119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64547858 + ... + 64549563.

It is an arithmetic number, because the mean of its divisors is an integer number (27562299597).

Almost surely, 2^110120100113 is an apocalyptic number.

It is an amenable number.

110120100113 is a deficient number, since it is larger than the sum of its proper divisors (129098275).

110120100113 is an equidigital number, since it uses as much as digits as its factorization.

110120100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129098274.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 110120100113 its reverse (311001021011), we get a palindrome (421121121124).

The spelling of 110120100113 in words is "one hundred ten billion, one hundred twenty million, one hundred thousand, one hundred thirteen".