Base | Representation |
---|---|
bin | 1010000000111111010110… |
… | …0010011101111100110111 |
3 | 1102222202012121202122020001 |
4 | 2200033311202131330313 |
5 | 2420410310340230033 |
6 | 35230522014452131 |
7 | 2214412420646230 |
oct | 240176542357467 |
9 | 42882177678201 |
10 | 11012120633143 |
11 | 356623a014aa3 |
12 | 129a280b04047 |
13 | 61b591574a26 |
14 | 2a0dbd1d6087 |
15 | 1416b5807e7d |
hex | a03f589df37 |
11012120633143 has 4 divisors (see below), whose sum is σ = 12585280723600. Its totient is φ = 9438960542688.
The previous prime is 11012120633131. The next prime is 11012120633203. The reversal of 11012120633143 is 34133602121011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11012120633143 - 237 = 10874681679671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11012120633243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786580045218 + ... + 786580045231.
It is an arithmetic number, because the mean of its divisors is an integer number (3146320180900).
Almost surely, 211012120633143 is an apocalyptic number.
11012120633143 is a deficient number, since it is larger than the sum of its proper divisors (1573160090457).
11012120633143 is an equidigital number, since it uses as much as digits as its factorization.
11012120633143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1573160090456.
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 11012120633143 its reverse (34133602121011), we get a palindrome (45145722754154).
The spelling of 11012120633143 in words is "eleven trillion, twelve billion, one hundred twenty million, six hundred thirty-three thousand, one hundred forty-three".
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