1101285051133 has 4 divisors (see below), whose sum is σ = 1101525353568. Its totient is φ = 1101044748700.

The previous prime is 1101285051127. The next prime is 1101285051157. The reversal of 1101285051133 is 3311505821011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1101285051133 - 2¹⁷ = 1101284920061 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1101285051095 and 1101285051104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101285051193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120144343 + ... + 120153508.

It is an arithmetic number, because the mean of its divisors is an integer number (275381338392).

Almost surely, 2^{1101285051133} is an apocalyptic number.

It is an amenable number.

1101285051133 is a deficient number, since it is larger than the sum of its proper divisors (240302435).

1101285051133 is an equidigital number, since it uses as much as digits as its factorization.

1101285051133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 240302434.

The product of its (nonzero) digits is 3600, while the sum is 31.

The spelling of 1101285051133 in words is "one trillion, one hundred one billion, two hundred eighty-five million, fifty-one thousand, one hundred thirty-three".