Base | Representation |
---|---|
bin | 10000000001101010100… |
… | …110100110100100000111 |
3 | 10220021122111111022200121 |
4 | 100001222212212210013 |
5 | 121020430313211403 |
6 | 2201532535522411 |
7 | 142365146445103 |
oct | 20015246464407 |
9 | 3807574438617 |
10 | 1101300132103 |
11 | 395071239536 |
12 | 159533229407 |
13 | 7cb1025b402 |
14 | 3b436020903 |
15 | 1d9a9bba3bd |
hex | 1006a9a6907 |
1101300132103 has 4 divisors (see below), whose sum is σ = 1136825942848. Its totient is φ = 1065774321360.
The previous prime is 1101300132059. The next prime is 1101300132109. The reversal of 1101300132103 is 3012310031011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1101300132103 - 233 = 1092710197511 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1101300132109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17762905326 + ... + 17762905387.
It is an arithmetic number, because the mean of its divisors is an integer number (284206485712).
Almost surely, 21101300132103 is an apocalyptic number.
1101300132103 is a deficient number, since it is larger than the sum of its proper divisors (35525810745).
1101300132103 is an equidigital number, since it uses as much as digits as its factorization.
1101300132103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35525810744.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1101300132103 its reverse (3012310031011), we get a palindrome (4113610163114).
The spelling of 1101300132103 in words is "one trillion, one hundred one billion, three hundred million, one hundred thirty-two thousand, one hundred three".
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