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1101300300322 = 2550650150161
BaseRepresentation
bin10000000001101010100…
…111001111101000100010
310220021122111210212102221
4100001222213033220202
5121020430334102242
62201532543301254
7142365151045405
oct20015247175042
93807574725387
101101300300322
11395071343962
121595332aa82a
137cb102b9b51
143b436065d3c
151d9a9c00167
hex1006a9cfa22

1101300300322 has 4 divisors (see below), whose sum is σ = 1651950450486. Its totient is φ = 550650150160.

The previous prime is 1101300300307. The next prime is 1101300300329. The reversal of 1101300300322 is 2230030031011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 720612534321 + 380687766001 = 848889^2 + 616999^2 .

It is a super-3 number, since 3×11013003003223 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1101300300296 and 1101300300305.

It is not an unprimeable number, because it can be changed into a prime (1101300300329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275325075079 + ... + 275325075082.

Almost surely, 21101300300322 is an apocalyptic number.

1101300300322 is a deficient number, since it is larger than the sum of its proper divisors (550650150164).

1101300300322 is an equidigital number, since it uses as much as digits as its factorization.

1101300300322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 550650150163.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 1101300300322 its reverse (2230030031011), we get a palindrome (3331330331333).

The spelling of 1101300300322 in words is "one trillion, one hundred one billion, three hundred million, three hundred thousand, three hundred twenty-two".

Divisors: 1 2 550650150161 1101300300322