Base | Representation |
---|---|
bin | 10100100000110110… |
… | …11010011110010111 |
3 | 1001102111222101210020 |
4 | 22100123122132113 |
5 | 140023314240043 |
6 | 5020451400223 |
7 | 536625203256 |
oct | 122033323627 |
9 | 31374871706 |
10 | 11013040023 |
11 | 4741634a77 |
12 | 21742b3073 |
13 | 1066841b3b |
14 | 76690679d |
15 | 446cb7e83 |
hex | 2906da797 |
11013040023 has 4 divisors (see below), whose sum is σ = 14684053368. Its totient is φ = 7342026680.
The previous prime is 11013040001. The next prime is 11013040039. The reversal of 11013040023 is 32004031011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11013040023 - 29 = 11013039511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11013039984 and 11013040011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11013040823) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1835506668 + ... + 1835506673.
It is an arithmetic number, because the mean of its divisors is an integer number (3671013342).
Almost surely, 211013040023 is an apocalyptic number.
11013040023 is a deficient number, since it is larger than the sum of its proper divisors (3671013345).
11013040023 is an equidigital number, since it uses as much as digits as its factorization.
11013040023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3671013344.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 11013040023 its reverse (32004031011), we get a palindrome (43017071034).
The spelling of 11013040023 in words is "eleven billion, thirteen million, forty thousand, twenty-three".
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