Search a number
-
+
110131031213000 = 23537891171150961
BaseRepresentation
bin11001000010100111100000…
…111111101000001111001000
3112102221102102220220002000222
4121002213200333220033020
5103413341322442304000
61030121255225245212
732124463422455030
oct3102474077501710
9472842386802028
10110131031213000
1132100343011976
121042816b633808
13495b4089c12a5
141d2a5283608c0
15caeb62d70a85
hex6429e0fe83c8

110131031213000 has 256 divisors, whose sum is σ = 298087391347200. Its totient is φ = 37302819840000.

The previous prime is 110131031212997. The next prime is 110131031213051. The reversal of 110131031213000 is 312130131011.

It is a super-3 number, since 3×1101310312130003 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 110131031213000.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 729457520 + ... + 729608480.

It is an arithmetic number, because the mean of its divisors is an integer number (1164403872450).

Almost surely, 2110131031213000 is an apocalyptic number.

110131031213000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 110131031213000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (149043695673600).

110131031213000 is an abundant number, since it is smaller than the sum of its proper divisors (187956360134200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110131031213000 is a wasteful number, since it uses less digits than its factorization.

110131031213000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 152249 (or 152235 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 110131031213000 its reverse (312130131011), we get a palindrome (110443161344011).

The spelling of 110131031213000 in words is "one hundred ten trillion, one hundred thirty-one billion, thirty-one million, two hundred thirteen thousand".