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1101311314055 = 5792788129909
BaseRepresentation
bin10000000001101011010…
…001010000100010000111
310220021200021112102102222
4100001223101100202013
5121020441144022210
62201534015322555
7142365343466411
oct20015321204207
93807607472388
101101311314055
11395077586717
12159536b2045b
137cb12674c54
143b4376d19b1
151d9aab78655
hex1006b450887

1101311314055 has 8 divisors (see below), whose sum is σ = 1338302356800. Its totient is φ = 869896531296.

The previous prime is 1101311314031. The next prime is 1101311314067. The reversal of 1101311314055 is 5504131131011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1101311314055 - 216 = 1101311248519 is a prime.

It is a super-2 number, since 2×11013113140552 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1394064560 + ... + 1394065349.

It is an arithmetic number, because the mean of its divisors is an integer number (167287794600).

Almost surely, 21101311314055 is an apocalyptic number.

1101311314055 is a deficient number, since it is larger than the sum of its proper divisors (236991042745).

1101311314055 is an equidigital number, since it uses as much as digits as its factorization.

1101311314055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2788129993.

The product of its (nonzero) digits is 900, while the sum is 26.

Adding to 1101311314055 its reverse (5504131131011), we get a palindrome (6605442445066).

The spelling of 1101311314055 in words is "one trillion, one hundred one billion, three hundred eleven million, three hundred fourteen thousand, fifty-five".

Divisors: 1 5 79 395 2788129909 13940649545 220262262811 1101311314055