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11013210023 = 67164376269
BaseRepresentation
bin10100100000111000…
…00011111110100111
31001102112022000222112
422100130003332213
5140023340210043
65020455151235
7536626512014
oct122034037647
931375260875
1011013210023
114741740772
12217437551b
1310668a132a
1476694c70b
15446ced518
hex290703fa7

11013210023 has 4 divisors (see below), whose sum is σ = 11177586360. Its totient is φ = 10848833688.

The previous prime is 11013210017. The next prime is 11013210031. The reversal of 11013210023 is 32001231011.

11013210023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11013210023 - 218 = 11012947879 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013210223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82188068 + ... + 82188201.

It is an arithmetic number, because the mean of its divisors is an integer number (2794396590).

Almost surely, 211013210023 is an apocalyptic number.

11013210023 is a deficient number, since it is larger than the sum of its proper divisors (164376337).

11013210023 is an equidigital number, since it uses as much as digits as its factorization.

11013210023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164376336.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 11013210023 its reverse (32001231011), we get a palindrome (43014441034).

The spelling of 11013210023 in words is "eleven billion, thirteen million, two hundred ten thousand, twenty-three".

Divisors: 1 67 164376269 11013210023