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11013210110303 = 11502139574931
BaseRepresentation
bin1010000001000011011001…
…1110011111100101011111
31102222212000112210210220222
42200100312132133211133
52420420023242012203
635231222054031555
72214451420234412
oct240206636374537
942885015723828
1011013210110303
113566748aa2345
12129a5259485bb
1361b7061acb7b
142a1083b95b79
1514172b2b1038
hexa043679f95f

11013210110303 has 4 divisors (see below), whose sum is σ = 11013220835448. Its totient is φ = 11013199385160.

The previous prime is 11013210110293. The next prime is 11013210110321. The reversal of 11013210110303 is 30301101231011.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11013210110303 - 28 = 11013210110047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013210110323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3637253 + ... + 5937678.

It is an arithmetic number, because the mean of its divisors is an integer number (2753305208862).

Almost surely, 211013210110303 is an apocalyptic number.

11013210110303 is a deficient number, since it is larger than the sum of its proper divisors (10725145).

11013210110303 is an equidigital number, since it uses as much as digits as its factorization.

11013210110303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10725144.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11013210110303 its reverse (30301101231011), we get a palindrome (41314311341314).

The spelling of 11013210110303 in words is "eleven trillion, thirteen billion, two hundred ten million, one hundred ten thousand, three hundred three".

Divisors: 1 1150213 9574931 11013210110303