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1101321055301 = 10710292720143
BaseRepresentation
bin10000000001101011110…
…110011010110001000101
310220021200221212022220212
4100001223312122301011
5121021001142232201
62201535004205205
7142365522340505
oct20015366326105
93807627768825
101101321055301
1139508202a435
1215953a239805
137cb146a5abc
143b438b09a05
151d9ab94eabb
hex1006bd9ac45

1101321055301 has 4 divisors (see below), whose sum is σ = 1111613775552. Its totient is φ = 1091028335052.

The previous prime is 1101321055271. The next prime is 1101321055339. The reversal of 1101321055301 is 1035501231011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101321055301 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1101321052301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5146359965 + ... + 5146360178.

It is an arithmetic number, because the mean of its divisors is an integer number (277903443888).

Almost surely, 21101321055301 is an apocalyptic number.

It is an amenable number.

1101321055301 is a deficient number, since it is larger than the sum of its proper divisors (10292720251).

1101321055301 is a wasteful number, since it uses less digits than its factorization.

1101321055301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10292720250.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 1101321055301 its reverse (1035501231011), we get a palindrome (2136822286312).

The spelling of 1101321055301 in words is "one trillion, one hundred one billion, three hundred twenty-one million, fifty-five thousand, three hundred one".

Divisors: 1 107 10292720143 1101321055301