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11013231103 = 71573318729
BaseRepresentation
bin10100100000111000…
…01001000111111111
31001102112100002220021
422100130021013333
5140023341343403
65020455433011
7536626630330
oct122034110777
931375302807
1011013231103
114741755596
122174385767
1310668aaac4
14766956287
15446d048bd
hex2907091ff

11013231103 has 4 divisors (see below), whose sum is σ = 12586549840. Its totient is φ = 9439912368.

The previous prime is 11013231049. The next prime is 11013231121. The reversal of 11013231103 is 30113231011.

11013231103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11013231103 - 217 = 11013100031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013231143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 786659358 + ... + 786659371.

It is an arithmetic number, because the mean of its divisors is an integer number (3146637460).

Almost surely, 211013231103 is an apocalyptic number.

11013231103 is a deficient number, since it is larger than the sum of its proper divisors (1573318737).

11013231103 is an equidigital number, since it uses as much as digits as its factorization.

11013231103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1573318736.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11013231103 its reverse (30113231011), we get a palindrome (41126462114).

The spelling of 11013231103 in words is "eleven billion, thirteen million, two hundred thirty-one thousand, one hundred three".

Divisors: 1 7 1573318729 11013231103